Solve 1/6b-2/3b+1/2b

$$\frac { 1 } { 6 b } - \frac { 2 } { 3 b } + \frac { 1 } { 2 b }$$

Evaluate

$$0$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 6b and 3b is 6b. Multiply \frac{2}{3b} times \frac{2}{2}.

$$\frac{1}{6b}-\frac{2\times 2}{6b}+\frac{1}{2b}$$

Since \frac{1}{6b} and \frac{2\times 2}{6b} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1-2\times 2}{6b}+\frac{1}{2b}$$

Do the multiplications in 1-2\times 2.

$$\frac{1-4}{6b}+\frac{1}{2b}$$

Do the calculations in 1-4.

$$\frac{-3}{6b}+\frac{1}{2b}$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 6b and 2b is 6b. Multiply \frac{1}{2b} times \frac{3}{3}.

$$\frac{-3}{6b}+\frac{3}{6b}$$

Since \frac{-3}{6b} and \frac{3}{6b} have the same denominator, add them by adding their numerators. Add -3 and 3 to get 0.

$$\frac{0}{6b}$$

Zero divided by any non-zero term gives zero.

$$0$$

Factor

$$0$$