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\frac{1}{6}x+\frac{2}{3}+\frac{1}{2}x=\frac{2}{3}
Add \frac{1}{2}x to both sides.
\frac{2}{3}x+\frac{2}{3}=\frac{2}{3}
Combine \frac{1}{6}x and \frac{1}{2}x to get \frac{2}{3}x.
\frac{2}{3}x=\frac{2}{3}-\frac{2}{3}
Subtract \frac{2}{3} from both sides.
\frac{2}{3}x=0
Subtract \frac{2}{3} from \frac{2}{3} to get 0.
x=0
Product of two numbers is equal to 0 if at least one of them is 0. Since \frac{2}{3} is not equal to 0, x must be equal to 0.