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\frac{1}{6}\left(x+0\right)^{2}-3
Multiply -1 and 0 to get 0.
\frac{1}{6}x^{2}-3
Anything plus zero gives itself.
\frac{x^{2}-18}{6}
Factor out \frac{1}{6}. Polynomial x^{2}-18 is not factored since it does not have any rational roots.