Solve 1/6(-30-3y/3)+y=15

$$\frac { 1 } { 6 } ( \frac { - 30 - 3 y } { 3 } ) + y = 15$$

Solve for y

$$y=20$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 6, the least common multiple of 6,3.

$$\frac{1}{3}\left(-30-3y\right)+6y=90$$

Use the distributive property to multiply \frac{1}{3} by -30-3y.

$$\frac{1}{3}\left(-30\right)+\frac{1}{3}\left(-3\right)y+6y=90$$

Multiply \frac{1}{3} and -30 to get \frac{-30}{3}.

$$\frac{-30}{3}+\frac{1}{3}\left(-3\right)y+6y=90$$

Divide -30 by 3 to get -10.

$$-10+\frac{1}{3}\left(-3\right)y+6y=90$$

Multiply \frac{1}{3} and -3 to get \frac{-3}{3}.

$$-10+\frac{-3}{3}y+6y=90$$

Divide -3 by 3 to get -1.

$$-10-y+6y=90$$

Combine -y and 6y to get 5y.

$$-10+5y=90$$

Add 10 to both sides.

$$5y=90+10$$

Add 90 and 10 to get 100.

$$5y=100$$

Divide both sides by 5.

$$y=\frac{100}{5}$$

Divide 100 by 5 to get 20.

$$y=20$$