Solve 1/6*2/3+1/3

$$\frac { 1 } { 6 } \times \frac { 2 } { 3 } + \frac { 1 } { 3 }$$

Evaluate

$$\frac{4}{9}\approx 0.444444444$$

Solution Steps

Multiply \frac{1}{6} times \frac{2}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 2}{6\times 3}+\frac{1}{3}$$

Do the multiplications in the fraction \frac{1\times 2}{6\times 3}.

$$\frac{2}{18}+\frac{1}{3}$$

Reduce the fraction \frac{2}{18} to lowest terms by extracting and canceling out 2.

$$\frac{1}{9}+\frac{1}{3}$$

Least common multiple of 9 and 3 is 9. Convert \frac{1}{9} and \frac{1}{3} to fractions with denominator 9.

$$\frac{1}{9}+\frac{3}{9}$$

Since \frac{1}{9} and \frac{3}{9} have the same denominator, add them by adding their numerators.

$$\frac{1+3}{9}$$

Add 1 and 3 to get 4.

$$\frac{4}{9}$$

Factor

$$\frac{2 ^ {2}}{3 ^ {2}} = 0.4444444444444444$$