Solve 1/6*3/4+1/12+2/4-frac{1}{24}

$$\frac { 1 } { 6 } \cdot \frac { 3 } { 4 } + \frac { 1 } { 12 } + \frac { 2 } { 4 } - \frac { 1 } { 24 }$$

Evaluate

$$\frac{2}{3}\approx 0.666666667$$

Solution Steps

Multiply \frac{1}{6} times \frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 3}{6\times 4}+\frac{1}{12}+\frac{2}{4}-\frac{1}{24}$$

Do the multiplications in the fraction \frac{1\times 3}{6\times 4}.

$$\frac{3}{24}+\frac{1}{12}+\frac{2}{4}-\frac{1}{24}$$

Reduce the fraction \frac{3}{24} to lowest terms by extracting and canceling out 3.

$$\frac{1}{8}+\frac{1}{12}+\frac{2}{4}-\frac{1}{24}$$

Least common multiple of 8 and 12 is 24. Convert \frac{1}{8} and \frac{1}{12} to fractions with denominator 24.

$$\frac{3}{24}+\frac{2}{24}+\frac{2}{4}-\frac{1}{24}$$

Since \frac{3}{24} and \frac{2}{24} have the same denominator, add them by adding their numerators.

$$\frac{3+2}{24}+\frac{2}{4}-\frac{1}{24}$$

Add 3 and 2 to get 5.

$$\frac{5}{24}+\frac{2}{4}-\frac{1}{24}$$

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$\frac{5}{24}+\frac{1}{2}-\frac{1}{24}$$

Least common multiple of 24 and 2 is 24. Convert \frac{5}{24} and \frac{1}{2} to fractions with denominator 24.

$$\frac{5}{24}+\frac{12}{24}-\frac{1}{24}$$

Since \frac{5}{24} and \frac{12}{24} have the same denominator, add them by adding their numerators.

$$\frac{5+12}{24}-\frac{1}{24}$$

Add 5 and 12 to get 17.

$$\frac{17}{24}-\frac{1}{24}$$

Since \frac{17}{24} and \frac{1}{24} have the same denominator, subtract them by subtracting their numerators.

$$\frac{17-1}{24}$$

Subtract 1 from 17 to get 16.

$$\frac{16}{24}$$

Reduce the fraction \frac{16}{24} to lowest terms by extracting and canceling out 8.

$$\frac{2}{3}$$

Factor

$$\frac{2}{3} = 0.6666666666666666$$