Solve 1/6=1/2*3=1/2-1/3

$$\frac { 1 } { 6 } = \frac { 1 } { 2 \times 3 } = \frac { 1 } { 2 } - \frac { 1 } { 3 }$$

Verify

Solution Steps

Multiply 2 and 3 to get 6.

$$\frac{1}{6}=\frac{1}{6}\text{ and }\frac{1}{2\times 3}=\frac{1}{2}-\frac{1}{3}$$

Compare \frac{1}{6} and \frac{1}{6}.

$$\text{true}\text{ and }\frac{1}{2\times 3}=\frac{1}{2}-\frac{1}{3}$$

Multiply 2 and 3 to get 6.

$$\text{true}\text{ and }\frac{1}{6}=\frac{1}{2}-\frac{1}{3}$$

Least common multiple of 2 and 3 is 6. Convert \frac{1}{2} and \frac{1}{3} to fractions with denominator 6.

$$\text{true}\text{ and }\frac{1}{6}=\frac{3}{6}-\frac{2}{6}$$

Since \frac{3}{6} and \frac{2}{6} have the same denominator, subtract them by subtracting their numerators.

$$\text{true}\text{ and }\frac{1}{6}=\frac{3-2}{6}$$

Subtract 2 from 3 to get 1.

$$\text{true}\text{ and }\frac{1}{6}=\frac{1}{6}$$

Compare \frac{1}{6} and \frac{1}{6}.

$$\text{true}\text{ and }\text{true}$$

The conjunction of \text{true} and \text{true} is \text{true}.

$$\text{true}$$