Solve 1/6+4*2-1/3

$$\frac { 1 } { 6 } + 4 \times 2 - \frac { 1 } { 3 }$$

Evaluate

$$\frac{47}{6}\approx 7.833333333$$

Solution Steps

Multiply 4 and 2 to get 8.

$$\frac{1}{6}+8-\frac{1}{3}$$

Convert 8 to fraction \frac{48}{6}.

$$\frac{1}{6}+\frac{48}{6}-\frac{1}{3}$$

Since \frac{1}{6} and \frac{48}{6} have the same denominator, add them by adding their numerators.

$$\frac{1+48}{6}-\frac{1}{3}$$

Add 1 and 48 to get 49.

$$\frac{49}{6}-\frac{1}{3}$$

Least common multiple of 6 and 3 is 6. Convert \frac{49}{6} and \frac{1}{3} to fractions with denominator 6.

$$\frac{49}{6}-\frac{2}{6}$$

Since \frac{49}{6} and \frac{2}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{49-2}{6}$$

Subtract 2 from 49 to get 47.

$$\frac{47}{6}$$

Factor

$$\frac{47}{2 \cdot 3} = 7\frac{5}{6} = 7.833333333333333$$