Solve 1/6+8/5+7/3

$$\frac { 1 } { 6 } + \frac { 8 } { 5 } + \frac { 7 } { 3 }$$

Evaluate

$$\frac{41}{10}=4.1$$

Solution Steps

Least common multiple of 6 and 5 is 30. Convert \frac{1}{6} and \frac{8}{5} to fractions with denominator 30.

$$\frac{5}{30}+\frac{48}{30}+\frac{7}{3}$$

Since \frac{5}{30} and \frac{48}{30} have the same denominator, add them by adding their numerators.

$$\frac{5+48}{30}+\frac{7}{3}$$

Add 5 and 48 to get 53.

$$\frac{53}{30}+\frac{7}{3}$$

Least common multiple of 30 and 3 is 30. Convert \frac{53}{30} and \frac{7}{3} to fractions with denominator 30.

$$\frac{53}{30}+\frac{70}{30}$$

Since \frac{53}{30} and \frac{70}{30} have the same denominator, add them by adding their numerators.

$$\frac{53+70}{30}$$

Add 53 and 70 to get 123.

$$\frac{123}{30}$$

Reduce the fraction \frac{123}{30} to lowest terms by extracting and canceling out 3.

$$\frac{41}{10}$$

Factor

$$\frac{41}{2 \cdot 5} = 4\frac{1}{10} = 4.1$$