Solve 1/6+5/8div4/7

$$\frac { 1 } { 6 } + \frac { 5 } { 8 } \div \frac { 4 } { 7 }$$

Evaluate

$$\frac{121}{96}\approx 1.260416667$$

Solution Steps

Divide \frac{5}{8} by \frac{4}{7} by multiplying \frac{5}{8} by the reciprocal of \frac{4}{7}.

$$\frac{1}{6}+\frac{5}{8}\times \frac{7}{4}$$

Multiply \frac{5}{8} times \frac{7}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1}{6}+\frac{5\times 7}{8\times 4}$$

Do the multiplications in the fraction \frac{5\times 7}{8\times 4}.

$$\frac{1}{6}+\frac{35}{32}$$

Least common multiple of 6 and 32 is 96. Convert \frac{1}{6} and \frac{35}{32} to fractions with denominator 96.

$$\frac{16}{96}+\frac{105}{96}$$

Since \frac{16}{96} and \frac{105}{96} have the same denominator, add them by adding their numerators.

$$\frac{16+105}{96}$$

Add 16 and 105 to get 121.

$$\frac{121}{96}$$

Factor

$$\frac{11 ^ {2}}{2 ^ {5} \cdot 3} = 1\frac{25}{96} = 1.2604166666666667$$