Solve 1/5x+1/25+x/50=x^2/50x

$$\frac { 1 } { 5 x } + \frac { 1 } { 25 } + \frac { x } { 50 } = \frac { x ^ { 2 } } { 50 x }$$

Solve for x

$$x=-5$$

Steps for Solving Linear Equation

Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 50x, the least common multiple of 5x,25,50,50x.

$$10+50x\times \frac{1}{25}+xx=x^{2}$$

Multiply x and x to get x^{2}.

$$10+50x\times \frac{1}{25}+x^{2}=x^{2}$$

Multiply 50 and \frac{1}{25} to get 2.

$$10+2x+x^{2}=x^{2}$$

Subtract x^{2} from both sides.

$$10+2x+x^{2}-x^{2}=0$$

Combine x^{2} and -x^{2} to get 0.

$$10+2x=0$$

Subtract 10 from both sides. Anything subtracted from zero gives its negation.

$$2x=-10$$

Divide both sides by 2.

$$x=\frac{-10}{2}$$

Divide -10 by 2 to get -5.

$$x=-5$$