Solve 1/5*5/8=1/8quad1-12/19

$$\frac { 1 } { 5 } \times \frac { 5 } { 8 } = \frac { 1 } { 8 } \quad 1 - \frac { 12 } { 19 }$$

Verify

Solution Steps

Multiply \frac{1}{5} times \frac{5}{8} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 5}{5\times 8}=\frac{1}{8}\times 1-\frac{12}{19}$$

Cancel out 5 in both numerator and denominator.

$$\frac{1}{8}=\frac{1}{8}\times 1-\frac{12}{19}$$

Multiply \frac{1}{8} and 1 to get \frac{1}{8}.

$$\frac{1}{8}=\frac{1}{8}-\frac{12}{19}$$

Least common multiple of 8 and 19 is 152. Convert \frac{1}{8} and \frac{12}{19} to fractions with denominator 152.

$$\frac{1}{8}=\frac{19}{152}-\frac{96}{152}$$

Since \frac{19}{152} and \frac{96}{152} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{8}=\frac{19-96}{152}$$

Subtract 96 from 19 to get -77.

$$\frac{1}{8}=-\frac{77}{152}$$

Least common multiple of 8 and 152 is 152. Convert \frac{1}{8} and -\frac{77}{152} to fractions with denominator 152.

$$\frac{19}{152}=-\frac{77}{152}$$

Compare \frac{19}{152} and -\frac{77}{152}.

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