Solve 1/5sqrt{300}quad_3^2sqrt{27}+sqrt{48}

$$\frac { 1 } { 5 } \sqrt { 300 } \quad _ { 3 } ^ { 2 } \sqrt { 27 } + \sqrt { 48 }$$

Evaluate

$$2\sqrt{3}\approx 3.464101615$$

Solution Steps

Factor 300=10^{2}\times 3. Rewrite the square root of the product \sqrt{10^{2}\times 3} as the product of square roots \sqrt{10^{2}}\sqrt{3}. Take the square root of 10^{2}.

$$\frac{1}{5}\times 10\sqrt{3}$$

Multiply \frac{1}{5} and 10 to get \frac{10}{5}.

$$\frac{10}{5}\sqrt{3}$$

Divide 10 by 5 to get 2.

$$2\sqrt{3}$$