Solve 1/40+1/60+1/80=

$$\frac { 1 } { 40 } + \frac { 1 } { 60 } + \frac { 1 } { 80 } =$$

Evaluate

$$\frac{13}{240}\approx 0.054166667$$

Solution Steps

Least common multiple of 40 and 60 is 120. Convert \frac{1}{40} and \frac{1}{60} to fractions with denominator 120.

$$\frac{3}{120}+\frac{2}{120}+\frac{1}{80}$$

Since \frac{3}{120} and \frac{2}{120} have the same denominator, add them by adding their numerators.

$$\frac{3+2}{120}+\frac{1}{80}$$

Add 3 and 2 to get 5.

$$\frac{5}{120}+\frac{1}{80}$$

Reduce the fraction \frac{5}{120} to lowest terms by extracting and canceling out 5.

$$\frac{1}{24}+\frac{1}{80}$$

Least common multiple of 24 and 80 is 240. Convert \frac{1}{24} and \frac{1}{80} to fractions with denominator 240.

$$\frac{10}{240}+\frac{3}{240}$$

Since \frac{10}{240} and \frac{3}{240} have the same denominator, add them by adding their numerators.

$$\frac{10+3}{240}$$

Add 10 and 3 to get 13.

$$\frac{13}{240}$$

Factor

$$\frac{13}{2 ^ {4} \cdot 3 \cdot 5} = 0.05416666666666667$$