Solve 1/4y-3x^2=0

$$\frac { 1 } { 4 } y - 3 x ^ { 2 } = 0$$

Solve for y

$$y=12x^{2}$$

Steps for Solving Linear Equation

Add 3x^{2} to both sides. Anything plus zero gives itself.

$$\frac{1}{4}y=3x^{2}$$

Multiply both sides by 4.

$$\frac{\frac{1}{4}y}{\frac{1}{4}}=\frac{3x^{2}}{\frac{1}{4}}$$

Dividing by \frac{1}{4} undoes the multiplication by \frac{1}{4}.

$$y=\frac{3x^{2}}{\frac{1}{4}}$$

Divide 3x^{2} by \frac{1}{4} by multiplying 3x^{2} by the reciprocal of \frac{1}{4}.

$$y=12x^{2}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{3y}}{6}$$

$$x=\frac{\sqrt{3y}}{6}$$

Solve for x

$$x=\frac{\sqrt{3y}}{6}$$

$$x=-\frac{\sqrt{3y}}{6}\text{, }y\geq 0$$