Solve 1/4x-2y=12,text{when}y=-1?

$$\frac { 1 } { 4 } x - 2 y = 12 , \text { when } y = - 1 ?$$

Solve for x, y

$$x=40$$

$$y=-1$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$\frac{1}{4}x-2\left(-1\right)=12$$

Multiply -2 and -1 to get 2.

$$\frac{1}{4}x+2=12$$

Subtract 2 from both sides.

$$\frac{1}{4}x=12-2$$

Subtract 2 from 12 to get 10.

$$\frac{1}{4}x=10$$

Multiply both sides by 4, the reciprocal of \frac{1}{4}.

$$x=10\times 4$$

Multiply 10 and 4 to get 40.

$$x=40$$

The system is now solved.

$$x=40 y=-1$$