Solve 1/4x+2/3y=3/3

$$\frac { 1 } { 4 } x + \frac { 2 } { 3 } y = \frac { 3 } { 3 }$$

Solve for x

$$x=-\frac{8y}{3}+4$$

Steps for Solving Linear Equation

Divide 3 by 3 to get 1.

$$\frac{1}{4}x+\frac{2}{3}y=1$$

Subtract \frac{2}{3}y from both sides.

$$\frac{1}{4}x=1-\frac{2}{3}y$$

The equation is in standard form.

$$\frac{1}{4}x=-\frac{2y}{3}+1$$

Multiply both sides by 4.

$$\frac{\frac{1}{4}x}{\frac{1}{4}}=\frac{-\frac{2y}{3}+1}{\frac{1}{4}}$$

Dividing by \frac{1}{4} undoes the multiplication by \frac{1}{4}.

$$x=\frac{-\frac{2y}{3}+1}{\frac{1}{4}}$$

Divide 1-\frac{2y}{3} by \frac{1}{4} by multiplying 1-\frac{2y}{3} by the reciprocal of \frac{1}{4}.

$$x=-\frac{8y}{3}+4$$

Solve for y

$$y=-\frac{3x}{8}+\frac{3}{2}$$

Steps for Solving Linear Equation

Divide 3 by 3 to get 1.

$$\frac{1}{4}x+\frac{2}{3}y=1$$

Subtract \frac{1}{4}x from both sides.

$$\frac{2}{3}y=1-\frac{1}{4}x$$

The equation is in standard form.

$$\frac{2}{3}y=-\frac{x}{4}+1$$

Divide both sides of the equation by \frac{2}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{2}{3}y}{\frac{2}{3}}=\frac{-\frac{x}{4}+1}{\frac{2}{3}}$$

Dividing by \frac{2}{3} undoes the multiplication by \frac{2}{3}.

$$y=\frac{-\frac{x}{4}+1}{\frac{2}{3}}$$

Divide 1-\frac{x}{4} by \frac{2}{3} by multiplying 1-\frac{x}{4} by the reciprocal of \frac{2}{3}.

$$y=-\frac{3x}{8}+\frac{3}{2}$$