Solve 1/4x+1/3y=0

$$\frac { 1 } { 4 } x + \frac { 1 } { 3 } y = 0$$

Solve for x

$$x=-\frac{4y}{3}$$

Steps for Solving Linear Equation

Subtract \frac{1}{3}y from both sides. Anything subtracted from zero gives its negation.

$$\frac{1}{4}x=-\frac{1}{3}y$$

The equation is in standard form.

$$\frac{1}{4}x=-\frac{y}{3}$$

Multiply both sides by 4.

$$\frac{\frac{1}{4}x}{\frac{1}{4}}=-\frac{\frac{y}{3}}{\frac{1}{4}}$$

Dividing by \frac{1}{4} undoes the multiplication by \frac{1}{4}.

$$x=-\frac{\frac{y}{3}}{\frac{1}{4}}$$

Divide -\frac{y}{3} by \frac{1}{4} by multiplying -\frac{y}{3} by the reciprocal of \frac{1}{4}.

$$x=-\frac{4y}{3}$$

Solve for y

$$y=-\frac{3x}{4}$$

Steps for Solving Linear Equation

Subtract \frac{1}{4}x from both sides. Anything subtracted from zero gives its negation.

$$\frac{1}{3}y=-\frac{1}{4}x$$

The equation is in standard form.

$$\frac{1}{3}y=-\frac{x}{4}$$

Multiply both sides by 3.

$$\frac{\frac{1}{3}y}{\frac{1}{3}}=-\frac{\frac{x}{4}}{\frac{1}{3}}$$

Dividing by \frac{1}{3} undoes the multiplication by \frac{1}{3}.

$$y=-\frac{\frac{x}{4}}{\frac{1}{3}}$$

Divide -\frac{x}{4} by \frac{1}{3} by multiplying -\frac{x}{4} by the reciprocal of \frac{1}{3}.

$$y=-\frac{3x}{4}$$