Solve 1/4(8x-16)=1/3(12x-6)

$$\frac { 1 } { 4 } ( 8 x - 16 ) = \frac { 1 } { 3 } ( 12 x - 6 )$$

Solve for x

$$x=-1$$

Steps for Solving Linear Equation

Use the distributive property to multiply \frac{1}{4} by 8x-16.

$$\frac{1}{4}\times 8x+\frac{1}{4}\left(-16\right)=\frac{1}{3}\left(12x-6\right)$$

Multiply \frac{1}{4} and 8 to get \frac{8}{4}.

$$\frac{8}{4}x+\frac{1}{4}\left(-16\right)=\frac{1}{3}\left(12x-6\right)$$

Divide 8 by 4 to get 2.

$$2x+\frac{1}{4}\left(-16\right)=\frac{1}{3}\left(12x-6\right)$$

Multiply \frac{1}{4} and -16 to get \frac{-16}{4}.

$$2x+\frac{-16}{4}=\frac{1}{3}\left(12x-6\right)$$

Divide -16 by 4 to get -4.

$$2x-4=\frac{1}{3}\left(12x-6\right)$$

Use the distributive property to multiply \frac{1}{3} by 12x-6.

$$2x-4=\frac{1}{3}\times 12x+\frac{1}{3}\left(-6\right)$$

Multiply \frac{1}{3} and 12 to get \frac{12}{3}.

$$2x-4=\frac{12}{3}x+\frac{1}{3}\left(-6\right)$$

Divide 12 by 3 to get 4.

$$2x-4=4x+\frac{1}{3}\left(-6\right)$$

Multiply \frac{1}{3} and -6 to get \frac{-6}{3}.

$$2x-4=4x+\frac{-6}{3}$$

Divide -6 by 3 to get -2.

$$2x-4=4x-2$$

Subtract 4x from both sides.

$$2x-4-4x=-2$$

Combine 2x and -4x to get -2x.

$$-2x-4=-2$$

Add 4 to both sides.

$$-2x=-2+4$$

Add -2 and 4 to get 2.

$$-2x=2$$

Divide both sides by -2.

$$x=\frac{2}{-2}$$

Divide 2 by -2 to get -1.

$$x=-1$$