Solve 1/4(6a-2b-4c)

$$\frac { 1 } { 4 } ( 6 a - 2 b - 4 c )$$

Evaluate

$$\frac{3a}{2}-\frac{b}{2}-c$$

Solution Steps

Use the distributive property to multiply \frac{1}{4} by 6a-2b-4c.

$$\frac{1}{4}\times 6a+\frac{1}{4}\left(-2\right)b+\frac{1}{4}\left(-4\right)c$$

Multiply \frac{1}{4} and 6 to get \frac{6}{4}.

$$\frac{6}{4}a+\frac{1}{4}\left(-2\right)b+\frac{1}{4}\left(-4\right)c$$

Reduce the fraction \frac{6}{4} to lowest terms by extracting and canceling out 2.

$$\frac{3}{2}a+\frac{1}{4}\left(-2\right)b+\frac{1}{4}\left(-4\right)c$$

Multiply \frac{1}{4} and -2 to get \frac{-2}{4}.

$$\frac{3}{2}a+\frac{-2}{4}b+\frac{1}{4}\left(-4\right)c$$

Reduce the fraction \frac{-2}{4} to lowest terms by extracting and canceling out 2.

$$\frac{3}{2}a-\frac{1}{2}b+\frac{1}{4}\left(-4\right)c$$

Multiply \frac{1}{4} and -4 to get \frac{-4}{4}.

$$\frac{3}{2}a-\frac{1}{2}b+\frac{-4}{4}c$$

Divide -4 by 4 to get -1.

$$\frac{3}{2}a-\frac{1}{2}b-c$$

Expand

$$\frac{3a}{2}-\frac{b}{2}-c$$

Solution Steps

Use the distributive property to multiply \frac{1}{4} by 6a-2b-4c.

$$\frac{1}{4}\times 6a+\frac{1}{4}\left(-2\right)b+\frac{1}{4}\left(-4\right)c$$

Multiply \frac{1}{4} and 6 to get \frac{6}{4}.

$$\frac{6}{4}a+\frac{1}{4}\left(-2\right)b+\frac{1}{4}\left(-4\right)c$$

Reduce the fraction \frac{6}{4} to lowest terms by extracting and canceling out 2.

$$\frac{3}{2}a+\frac{1}{4}\left(-2\right)b+\frac{1}{4}\left(-4\right)c$$

Multiply \frac{1}{4} and -2 to get \frac{-2}{4}.

$$\frac{3}{2}a+\frac{-2}{4}b+\frac{1}{4}\left(-4\right)c$$

Reduce the fraction \frac{-2}{4} to lowest terms by extracting and canceling out 2.

$$\frac{3}{2}a-\frac{1}{2}b+\frac{1}{4}\left(-4\right)c$$

Multiply \frac{1}{4} and -4 to get \frac{-4}{4}.

$$\frac{3}{2}a-\frac{1}{2}b+\frac{-4}{4}c$$

Divide -4 by 4 to get -1.

$$\frac{3}{2}a-\frac{1}{2}b-c$$