Solve 1/4(-283)^4-2(-283)^2

$$\frac { 1 } { 4 } ( - 283 ) ^ { 4 } - 2 ( - 283 ) ^ { 2 }$$

Evaluate

$$\frac{6413607209}{4}=1603401802.25$$

Solution Steps

Calculate -283 to the power of 4 and get 6414247921.

$$\frac{1}{4}\times 6414247921-2\left(-283\right)^{2}$$

Multiply \frac{1}{4} and 6414247921 to get \frac{6414247921}{4}.

$$\frac{6414247921}{4}-2\left(-283\right)^{2}$$

Calculate -283 to the power of 2 and get 80089.

$$\frac{6414247921}{4}-2\times 80089$$

Multiply 2 and 80089 to get 160178.

$$\frac{6414247921}{4}-160178$$

Convert 160178 to fraction \frac{640712}{4}.

$$\frac{6414247921}{4}-\frac{640712}{4}$$

Since \frac{6414247921}{4} and \frac{640712}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{6414247921-640712}{4}$$

Subtract 640712 from 6414247921 to get 6413607209.

$$\frac{6413607209}{4}$$

Factor

$$\frac{73 \cdot 283 ^ {2} \cdot 1097}{2 ^ {2}} = 1603401802\frac{1}{4} = 1603401802.25$$