Solve 1/4(1/2-1/3)=1/8-frac{1}{12}

$$\frac { 1 } { 4 } ( \frac { 1 } { 2 } - \frac { 1 } { 3 } ) = \frac { 1 } { 8 } - \frac { 1 } { 12 }$$

Verify

Solution Steps

Least common multiple of 2 and 3 is 6. Convert \frac{1}{2} and \frac{1}{3} to fractions with denominator 6.

$$\frac{1}{4}\left(\frac{3}{6}-\frac{2}{6}\right)=\frac{1}{8}-\frac{1}{12}$$

Since \frac{3}{6} and \frac{2}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{4}\times \frac{3-2}{6}=\frac{1}{8}-\frac{1}{12}$$

Subtract 2 from 3 to get 1.

$$\frac{1}{4}\times \frac{1}{6}=\frac{1}{8}-\frac{1}{12}$$

Multiply \frac{1}{4} times \frac{1}{6} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 1}{4\times 6}=\frac{1}{8}-\frac{1}{12}$$

Do the multiplications in the fraction \frac{1\times 1}{4\times 6}.

$$\frac{1}{24}=\frac{1}{8}-\frac{1}{12}$$

Least common multiple of 8 and 12 is 24. Convert \frac{1}{8} and \frac{1}{12} to fractions with denominator 24.

$$\frac{1}{24}=\frac{3}{24}-\frac{2}{24}$$

Since \frac{3}{24} and \frac{2}{24} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{24}=\frac{3-2}{24}$$

Subtract 2 from 3 to get 1.

$$\frac{1}{24}=\frac{1}{24}$$

Compare \frac{1}{24} and \frac{1}{24}.

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