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\frac{\frac{1}{4}}{\frac{39}{13}-\frac{5}{13}+\frac{8}{13}}
Convert 3 to fraction \frac{39}{13}.
\frac{\frac{1}{4}}{\frac{39-5}{13}+\frac{8}{13}}
Since \frac{39}{13} and \frac{5}{13} have the same denominator, subtract them by subtracting their numerators.
\frac{\frac{1}{4}}{\frac{34}{13}+\frac{8}{13}}
Subtract 5 from 39 to get 34.
\frac{\frac{1}{4}}{\frac{34+8}{13}}
Since \frac{34}{13} and \frac{8}{13} have the same denominator, add them by adding their numerators.
\frac{\frac{1}{4}}{\frac{42}{13}}
Add 34 and 8 to get 42.
\frac{1}{4}\times \frac{13}{42}
Divide \frac{1}{4} by \frac{42}{13} by multiplying \frac{1}{4} by the reciprocal of \frac{42}{13}.
\frac{1\times 13}{4\times 42}
Multiply \frac{1}{4} times \frac{13}{42} by multiplying numerator times numerator and denominator times denominator.
\frac{13}{168}
Do the multiplications in the fraction \frac{1\times 13}{4\times 42}.