Solve 1/4+(1/3+1/3)*9/5

$$\frac { 1 } { 4 } + ( \frac { 1 } { 3 } + \frac { 1 } { 3 } ) \cdot \frac { 9 } { 5 }$$

Evaluate

$$\frac{29}{20}=1.45$$

Solution Steps

Since \frac{1}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$\frac{1}{4}+\frac{1+1}{3}\times \frac{9}{5}$$

Add 1 and 1 to get 2.

$$\frac{1}{4}+\frac{2}{3}\times \frac{9}{5}$$

Multiply \frac{2}{3} times \frac{9}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1}{4}+\frac{2\times 9}{3\times 5}$$

Do the multiplications in the fraction \frac{2\times 9}{3\times 5}.

$$\frac{1}{4}+\frac{18}{15}$$

Reduce the fraction \frac{18}{15} to lowest terms by extracting and canceling out 3.

$$\frac{1}{4}+\frac{6}{5}$$

Least common multiple of 4 and 5 is 20. Convert \frac{1}{4} and \frac{6}{5} to fractions with denominator 20.

$$\frac{5}{20}+\frac{24}{20}$$

Since \frac{5}{20} and \frac{24}{20} have the same denominator, add them by adding their numerators.

$$\frac{5+24}{20}$$

Add 5 and 24 to get 29.

$$\frac{29}{20}$$

Factor

$$\frac{29}{2 ^ {2} \cdot 5} = 1\frac{9}{20} = 1.45$$