Solve 1/4+3/4-7/4-11/4=

$$\frac { 1 } { 4 } + \frac { 3 } { 4 } - \frac { 7 } { 4 } - \frac { 11 } { 4 } =$$

Evaluate

$$-\frac{7}{2}=-3.5$$

Solution Steps

Since \frac{1}{4} and \frac{3}{4} have the same denominator, add them by adding their numerators.

$$\frac{1+3}{4}-\frac{7}{4}-\frac{11}{4}$$

Add 1 and 3 to get 4.

$$\frac{4}{4}-\frac{7}{4}-\frac{11}{4}$$

Since \frac{4}{4} and \frac{7}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4-7}{4}-\frac{11}{4}$$

Subtract 7 from 4 to get -3.

$$-\frac{3}{4}-\frac{11}{4}$$

Since -\frac{3}{4} and \frac{11}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-3-11}{4}$$

Subtract 11 from -3 to get -14.

$$\frac{-14}{4}$$

Reduce the fraction \frac{-14}{4} to lowest terms by extracting and canceling out 2.

$$-\frac{7}{2}$$

Factor

$$-\frac{7}{2} = -3\frac{1}{2} = -3.5$$