Solve 1/4+2/3div1/5-3/4*2

$$\frac { 1 } { 4 } + \frac { 2 } { 3 } \div \frac { 1 } { 5 } - \frac { 3 } { 4 } \cdot 2$$

Evaluate

$$\frac{25}{12}\approx 2.083333333$$

Solution Steps

Divide \frac{2}{3} by \frac{1}{5} by multiplying \frac{2}{3} by the reciprocal of \frac{1}{5}.

$$\frac{1}{4}+\frac{2}{3}\times 5-\frac{3}{4}\times 2$$

Express \frac{2}{3}\times 5 as a single fraction.

$$\frac{1}{4}+\frac{2\times 5}{3}-\frac{3}{4}\times 2$$

Multiply 2 and 5 to get 10.

$$\frac{1}{4}+\frac{10}{3}-\frac{3}{4}\times 2$$

Least common multiple of 4 and 3 is 12. Convert \frac{1}{4} and \frac{10}{3} to fractions with denominator 12.

$$\frac{3}{12}+\frac{40}{12}-\frac{3}{4}\times 2$$

Since \frac{3}{12} and \frac{40}{12} have the same denominator, add them by adding their numerators.

$$\frac{3+40}{12}-\frac{3}{4}\times 2$$

Add 3 and 40 to get 43.

$$\frac{43}{12}-\frac{3}{4}\times 2$$

Express \frac{3}{4}\times 2 as a single fraction.

$$\frac{43}{12}-\frac{3\times 2}{4}$$

Multiply 3 and 2 to get 6.

$$\frac{43}{12}-\frac{6}{4}$$

Reduce the fraction \frac{6}{4} to lowest terms by extracting and canceling out 2.

$$\frac{43}{12}-\frac{3}{2}$$

Least common multiple of 12 and 2 is 12. Convert \frac{43}{12} and \frac{3}{2} to fractions with denominator 12.

$$\frac{43}{12}-\frac{18}{12}$$

Since \frac{43}{12} and \frac{18}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{43-18}{12}$$

Subtract 18 from 43 to get 25.

$$\frac{25}{12}$$

Factor

$$\frac{5 ^ {2}}{2 ^ {2} \cdot 3} = 2\frac{1}{12} = 2.0833333333333335$$