Solve 1/4+1/3+1/5+1/20+m=1

$$\frac { 1 } { 4 } + \frac { 1 } { 3 } + \frac { 1 } { 5 } + \frac { 1 } { 20 } + m = 1$$

Solve for m

$$m=\frac{1}{6}\approx 0.166666667$$

Steps for Solving Linear Equation

Least common multiple of 4 and 3 is 12. Convert \frac{1}{4} and \frac{1}{3} to fractions with denominator 12.

$$\frac{3}{12}+\frac{4}{12}+\frac{1}{5}+\frac{1}{20}+m=1$$

Since \frac{3}{12} and \frac{4}{12} have the same denominator, add them by adding their numerators.

$$\frac{3+4}{12}+\frac{1}{5}+\frac{1}{20}+m=1$$

Add 3 and 4 to get 7.

$$\frac{7}{12}+\frac{1}{5}+\frac{1}{20}+m=1$$

Least common multiple of 12 and 5 is 60. Convert \frac{7}{12} and \frac{1}{5} to fractions with denominator 60.

$$\frac{35}{60}+\frac{12}{60}+\frac{1}{20}+m=1$$

Since \frac{35}{60} and \frac{12}{60} have the same denominator, add them by adding their numerators.

$$\frac{35+12}{60}+\frac{1}{20}+m=1$$

Add 35 and 12 to get 47.

$$\frac{47}{60}+\frac{1}{20}+m=1$$

Least common multiple of 60 and 20 is 60. Convert \frac{47}{60} and \frac{1}{20} to fractions with denominator 60.

$$\frac{47}{60}+\frac{3}{60}+m=1$$

Since \frac{47}{60} and \frac{3}{60} have the same denominator, add them by adding their numerators.

$$\frac{47+3}{60}+m=1$$

Add 47 and 3 to get 50.

$$\frac{50}{60}+m=1$$

Reduce the fraction \frac{50}{60} to lowest terms by extracting and canceling out 10.

$$\frac{5}{6}+m=1$$

Subtract \frac{5}{6} from both sides.

$$m=1-\frac{5}{6}$$

Convert 1 to fraction \frac{6}{6}.

$$m=\frac{6}{6}-\frac{5}{6}$$

Since \frac{6}{6} and \frac{5}{6} have the same denominator, subtract them by subtracting their numerators.

$$m=\frac{6-5}{6}$$

Subtract 5 from 6 to get 1.

$$m=\frac{1}{6}$$