Solve 1/3x+2/x-1/7y=

$$\frac { 1 } { 3 x } + \frac { 2 } { x } - \frac { 1 } { 7 y } =$$

Evaluate

$$\frac{49y-3x}{21xy}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 3x and x is 3x. Multiply \frac{2}{x} times \frac{3}{3}.

$$\frac{1}{3x}+\frac{2\times 3}{3x}-\frac{1}{7y}$$

Since \frac{1}{3x} and \frac{2\times 3}{3x} have the same denominator, add them by adding their numerators.

$$\frac{1+2\times 3}{3x}-\frac{1}{7y}$$

Do the multiplications in 1+2\times 3.

$$\frac{1+6}{3x}-\frac{1}{7y}$$

Do the calculations in 1+6.

$$\frac{7}{3x}-\frac{1}{7y}$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 3x and 7y is 21xy. Multiply \frac{7}{3x} times \frac{7y}{7y}. Multiply \frac{1}{7y} times \frac{3x}{3x}.

$$\frac{7\times 7y}{21xy}-\frac{3x}{21xy}$$

Since \frac{7\times 7y}{21xy} and \frac{3x}{21xy} have the same denominator, subtract them by subtracting their numerators.

$$\frac{7\times 7y-3x}{21xy}$$

Do the multiplications in 7\times 7y-3x.

$$\frac{49y-3x}{21xy}$$

Factor

$$\frac{-\frac{3x}{y}+49}{21x}$$