Solve 1/3y-x=1

$$\frac { 1 } { 3 } y - x = 1$$

Solve for x

$$x=\frac{y-3}{3}$$

Steps for Solving Linear Equation

Subtract \frac{1}{3}y from both sides.

$$-x=1-\frac{1}{3}y$$

The equation is in standard form.

$$-x=-\frac{y}{3}+1$$

Divide both sides by -1.

$$\frac{-x}{-1}=\frac{-\frac{y}{3}+1}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$x=\frac{-\frac{y}{3}+1}{-1}$$

Divide 1-\frac{y}{3} by -1.

$$x=\frac{y}{3}-1$$

Solve for y

$$y=3\left(x+1\right)$$

Steps for Solving Linear Equation

Add x to both sides.

$$\frac{1}{3}y=1+x$$

The equation is in standard form.

$$\frac{1}{3}y=x+1$$

Multiply both sides by 3.

$$\frac{\frac{1}{3}y}{\frac{1}{3}}=\frac{x+1}{\frac{1}{3}}$$

Dividing by \frac{1}{3} undoes the multiplication by \frac{1}{3}.

$$y=\frac{x+1}{\frac{1}{3}}$$

Divide 1+x by \frac{1}{3} by multiplying 1+x by the reciprocal of \frac{1}{3}.

$$y=3x+3$$