Solve 1/3y+5/6y-1=2y-1

$$\frac { 1 } { 3 } y + \frac { 5 } { 6 } y - 1 = 2 y - 1$$

Solve for y

$$y=0$$

Steps for Solving Linear Equation

Combine \frac{1}{3}y and \frac{5}{6}y to get \frac{7}{6}y.

$$\frac{7}{6}y-1=2y-1$$

Subtract 2y from both sides.

$$\frac{7}{6}y-1-2y=-1$$

Combine \frac{7}{6}y and -2y to get -\frac{5}{6}y.

$$-\frac{5}{6}y-1=-1$$

Add 1 to both sides.

$$-\frac{5}{6}y=-1+1$$

Add -1 and 1 to get 0.

$$-\frac{5}{6}y=0$$

Product of two numbers is equal to 0 if at least one of them is 0. Since -\frac{5}{6} is not equal to 0, y must be equal to 0.

$$y=0$$