Solve for x
x\geq 3
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\frac{1}{3}x-7+3x\geq 3
Add 3x to both sides.
\frac{10}{3}x-7\geq 3
Combine \frac{1}{3}x and 3x to get \frac{10}{3}x.
\frac{10}{3}x\geq 3+7
Add 7 to both sides.
\frac{10}{3}x\geq 10
Add 3 and 7 to get 10.
x\geq 10\times \frac{3}{10}
Multiply both sides by \frac{3}{10}, the reciprocal of \frac{10}{3}. Since \frac{10}{3} is positive, the inequality direction remains the same.
x\geq 3
Cancel out 10 and 10.
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