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\frac{1}{3}x=\frac{5}{12}+\frac{3}{4}
Add \frac{3}{4} to both sides.
\frac{1}{3}x=\frac{5}{12}+\frac{9}{12}
Least common multiple of 12 and 4 is 12. Convert \frac{5}{12} and \frac{3}{4} to fractions with denominator 12.
\frac{1}{3}x=\frac{5+9}{12}
Since \frac{5}{12} and \frac{9}{12} have the same denominator, add them by adding their numerators.
\frac{1}{3}x=\frac{14}{12}
Add 5 and 9 to get 14.
\frac{1}{3}x=\frac{7}{6}
Reduce the fraction \frac{14}{12} to lowest terms by extracting and canceling out 2.
x=\frac{7}{6}\times 3
Multiply both sides by 3, the reciprocal of \frac{1}{3}.
x=\frac{7\times 3}{6}
Express \frac{7}{6}\times 3 as a single fraction.
x=\frac{21}{6}
Multiply 7 and 3 to get 21.
x=\frac{7}{2}
Reduce the fraction \frac{21}{6} to lowest terms by extracting and canceling out 3.