Solve 1/3x+sqrt{4}x-7=sqrt{26}x+1

$$\frac { 1 } { 3 } x + \sqrt { 4 } x - 7 = \sqrt { 26 } x + 1$$

Solve for x

$$x=\frac{-72\sqrt{26}-168}{185}\approx -2.892591378$$

Steps for Solving Linear Equation

Calculate the square root of 4 and get 2.

$$\frac{1}{3}x+2x-7=\sqrt{26}x+1$$

Combine \frac{1}{3}x and 2x to get \frac{7}{3}x.

$$\frac{7}{3}x-7=\sqrt{26}x+1$$

Subtract \sqrt{26}x from both sides.

$$\frac{7}{3}x-7-\sqrt{26}x=1$$

Add 7 to both sides.

$$\frac{7}{3}x-\sqrt{26}x=1+7$$

Add 1 and 7 to get 8.

$$\frac{7}{3}x-\sqrt{26}x=8$$

Combine all terms containing x.

$$\left(\frac{7}{3}-\sqrt{26}\right)x=8$$

Divide both sides by \frac{7}{3}-\sqrt{26}.

$$\frac{\left(\frac{7}{3}-\sqrt{26}\right)x}{\frac{7}{3}-\sqrt{26}}=\frac{8}{\frac{7}{3}-\sqrt{26}}$$

Dividing by \frac{7}{3}-\sqrt{26} undoes the multiplication by \frac{7}{3}-\sqrt{26}.

$$x=\frac{8}{\frac{7}{3}-\sqrt{26}}$$

Divide 8 by \frac{7}{3}-\sqrt{26}.

$$x=\frac{-72\sqrt{26}-168}{185}$$