Solve 1/3x+4/9=11/18

$$\frac { 1 } { 3 } x + \frac { 4 } { 9 } = \frac { 11 } { 18 }$$

Solve for x

$$x=\frac{1}{2}=0.5$$

Steps for Solving Linear Equation

Subtract \frac{4}{9} from both sides.

$$\frac{1}{3}x=\frac{11}{18}-\frac{4}{9}$$

Least common multiple of 18 and 9 is 18. Convert \frac{11}{18} and \frac{4}{9} to fractions with denominator 18.

$$\frac{1}{3}x=\frac{11}{18}-\frac{8}{18}$$

Since \frac{11}{18} and \frac{8}{18} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{3}x=\frac{11-8}{18}$$

Subtract 8 from 11 to get 3.

$$\frac{1}{3}x=\frac{3}{18}$$

Reduce the fraction \frac{3}{18} to lowest terms by extracting and canceling out 3.

$$\frac{1}{3}x=\frac{1}{6}$$

Multiply both sides by 3, the reciprocal of \frac{1}{3}.

$$x=\frac{1}{6}\times 3$$

Multiply \frac{1}{6} and 3 to get \frac{3}{6}.

$$x=\frac{3}{6}$$

Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.

$$x=\frac{1}{2}$$