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\frac{1}{3}x+\frac{1}{2}=\frac{4}{8}
Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.
\frac{1}{3}x+\frac{1}{2}=\frac{1}{2}
Reduce the fraction \frac{4}{8} to lowest terms by extracting and canceling out 4.
\frac{1}{3}x=\frac{1}{2}-\frac{1}{2}
Subtract \frac{1}{2} from both sides.
\frac{1}{3}x=0
Subtract \frac{1}{2} from \frac{1}{2} to get 0.
x=0
Product of two numbers is equal to 0 if at least one of them is 0. Since \frac{1}{3} is not equal to 0, x must be equal to 0.