Solve 1/3x+1/6y=-1

$$\frac { 1 } { 3 } x + \frac { 1 } { 6 } y = - 1$$

Solve for x

$$x=-\frac{y}{2}-3$$

Steps for Solving Linear Equation

Subtract \frac{1}{6}y from both sides.

$$\frac{1}{3}x=-1-\frac{1}{6}y$$

The equation is in standard form.

$$\frac{1}{3}x=-\frac{y}{6}-1$$

Multiply both sides by 3.

$$\frac{\frac{1}{3}x}{\frac{1}{3}}=\frac{-\frac{y}{6}-1}{\frac{1}{3}}$$

Dividing by \frac{1}{3} undoes the multiplication by \frac{1}{3}.

$$x=\frac{-\frac{y}{6}-1}{\frac{1}{3}}$$

Divide -1-\frac{y}{6} by \frac{1}{3} by multiplying -1-\frac{y}{6} by the reciprocal of \frac{1}{3}.

$$x=-\frac{y}{2}-3$$

Solve for y

$$y=-2x-6$$

Steps for Solving Linear Equation

Subtract \frac{1}{3}x from both sides.

$$\frac{1}{6}y=-1-\frac{1}{3}x$$

The equation is in standard form.

$$\frac{1}{6}y=-\frac{x}{3}-1$$

Multiply both sides by 6.

$$\frac{\frac{1}{6}y}{\frac{1}{6}}=\frac{-\frac{x}{3}-1}{\frac{1}{6}}$$

Dividing by \frac{1}{6} undoes the multiplication by \frac{1}{6}.

$$y=\frac{-\frac{x}{3}-1}{\frac{1}{6}}$$

Divide -1-\frac{x}{3} by \frac{1}{6} by multiplying -1-\frac{x}{3} by the reciprocal of \frac{1}{6}.

$$y=-2x-6$$