Solve 1/3x+1/2y=8

$$\frac { 1 } { 3 } x + \frac { 1 } { 2 } y = 8$$

Solve for x

$$x=-\frac{3y}{2}+24$$

Steps for Solving Linear Equation

Subtract \frac{1}{2}y from both sides.

$$\frac{1}{3}x=8-\frac{1}{2}y$$

The equation is in standard form.

$$\frac{1}{3}x=-\frac{y}{2}+8$$

Multiply both sides by 3.

$$\frac{\frac{1}{3}x}{\frac{1}{3}}=\frac{-\frac{y}{2}+8}{\frac{1}{3}}$$

Dividing by \frac{1}{3} undoes the multiplication by \frac{1}{3}.

$$x=\frac{-\frac{y}{2}+8}{\frac{1}{3}}$$

Divide 8-\frac{y}{2} by \frac{1}{3} by multiplying 8-\frac{y}{2} by the reciprocal of \frac{1}{3}.

$$x=-\frac{3y}{2}+24$$

Solve for y

$$y=-\frac{2x}{3}+16$$

Steps for Solving Linear Equation

Subtract \frac{1}{3}x from both sides.

$$\frac{1}{2}y=8-\frac{1}{3}x$$

The equation is in standard form.

$$\frac{1}{2}y=-\frac{x}{3}+8$$

Multiply both sides by 2.

$$\frac{\frac{1}{2}y}{\frac{1}{2}}=\frac{-\frac{x}{3}+8}{\frac{1}{2}}$$

Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.

$$y=\frac{-\frac{x}{3}+8}{\frac{1}{2}}$$

Divide 8-\frac{x}{3} by \frac{1}{2} by multiplying 8-\frac{x}{3} by the reciprocal of \frac{1}{2}.

$$y=-\frac{2x}{3}+16$$