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\frac{1}{3}-8x-2x=\frac{3}{4}
Subtract 2x from both sides.
\frac{1}{3}-10x=\frac{3}{4}
Combine -8x and -2x to get -10x.
-10x=\frac{3}{4}-\frac{1}{3}
Subtract \frac{1}{3} from both sides.
-10x=\frac{9}{12}-\frac{4}{12}
Least common multiple of 4 and 3 is 12. Convert \frac{3}{4} and \frac{1}{3} to fractions with denominator 12.
-10x=\frac{9-4}{12}
Since \frac{9}{12} and \frac{4}{12} have the same denominator, subtract them by subtracting their numerators.
-10x=\frac{5}{12}
Subtract 4 from 9 to get 5.
x=\frac{\frac{5}{12}}{-10}
Divide both sides by -10.
x=\frac{5}{12\left(-10\right)}
Express \frac{\frac{5}{12}}{-10} as a single fraction.
x=\frac{5}{-120}
Multiply 12 and -10 to get -120.
x=-\frac{1}{24}
Reduce the fraction \frac{5}{-120} to lowest terms by extracting and canceling out 5.