Solve 1/3-8+3*4+7*-2+1

$$\frac { 1 } { 3 } - 8 + 3 \cdot 4 + 7 \cdot - 2 + 1$$

Evaluate

$$-\frac{26}{3}\approx -8.666666667$$

Solution Steps

Multiply 3 and 4 to get 12. Multiply 7 and -2 to get -14.

$$\frac{1}{3}-8+12-14+1$$

Convert 8 to fraction \frac{24}{3}.

$$\frac{1}{3}-\frac{24}{3}+12-14+1$$

Since \frac{1}{3} and \frac{24}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1-24}{3}+12-14+1$$

Subtract 24 from 1 to get -23.

$$-\frac{23}{3}+12-14+1$$

Convert 12 to fraction \frac{36}{3}.

$$-\frac{23}{3}+\frac{36}{3}-14+1$$

Since -\frac{23}{3} and \frac{36}{3} have the same denominator, add them by adding their numerators.

$$\frac{-23+36}{3}-14+1$$

Add -23 and 36 to get 13.

$$\frac{13}{3}-14+1$$

Convert 14 to fraction \frac{42}{3}.

$$\frac{13}{3}-\frac{42}{3}+1$$

Since \frac{13}{3} and \frac{42}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{13-42}{3}+1$$

Subtract 42 from 13 to get -29.

$$-\frac{29}{3}+1$$

Convert 1 to fraction \frac{3}{3}.

$$-\frac{29}{3}+\frac{3}{3}$$

Since -\frac{29}{3} and \frac{3}{3} have the same denominator, add them by adding their numerators.

$$\frac{-29+3}{3}$$

Add -29 and 3 to get -26.

$$-\frac{26}{3}$$

Factor

$$-\frac{26}{3} = -8\frac{2}{3} = -8.666666666666666$$