Solve 1/3-3x=2/3+x

$$\frac { 1 } { 3 } - 3 x = \frac { 2 } { 3 } + x$$

Solve for x

$$x=-\frac{1}{12}\approx -0.083333333$$

Steps for Solving Linear Equation

Subtract x from both sides.

$$\frac{1}{3}-3x-x=\frac{2}{3}$$

Combine -3x and -x to get -4x.

$$\frac{1}{3}-4x=\frac{2}{3}$$

Subtract \frac{1}{3} from both sides.

$$-4x=\frac{2}{3}-\frac{1}{3}$$

Since \frac{2}{3} and \frac{1}{3} have the same denominator, subtract them by subtracting their numerators.

$$-4x=\frac{2-1}{3}$$

Subtract 1 from 2 to get 1.

$$-4x=\frac{1}{3}$$

Divide both sides by -4.

$$x=\frac{\frac{1}{3}}{-4}$$

Express \frac{\frac{1}{3}}{-4} as a single fraction.

$$x=\frac{1}{3\left(-4\right)}$$

Multiply 3 and -4 to get -12.

$$x=\frac{1}{-12}$$

Fraction \frac{1}{-12} can be rewritten as -\frac{1}{12} by extracting the negative sign.

$$x=-\frac{1}{12}$$