Solve 1/3-343/3-1/3*1/3

$$\frac { 1 } { 3 } - \frac { 343 } { 3 } - \frac { 1 } { 3 } \cdot \frac { 1 } { 3 }$$

Evaluate

$$-\frac{1027}{9}\approx -114.111111111$$

Solution Steps

Since \frac{1}{3} and \frac{343}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1-343}{3}-\frac{1}{3}\times \frac{1}{3}$$

Subtract 343 from 1 to get -342.

$$\frac{-342}{3}-\frac{1}{3}\times \frac{1}{3}$$

Divide -342 by 3 to get -114.

$$-114-\frac{1}{3}\times \frac{1}{3}$$

Multiply \frac{1}{3} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$-114-\frac{1\times 1}{3\times 3}$$

Do the multiplications in the fraction \frac{1\times 1}{3\times 3}.

$$-114-\frac{1}{9}$$

Convert -114 to fraction -\frac{1026}{9}.

$$-\frac{1026}{9}-\frac{1}{9}$$

Since -\frac{1026}{9} and \frac{1}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-1026-1}{9}$$

Subtract 1 from -1026 to get -1027.

$$-\frac{1027}{9}$$

Factor

$$-\frac{1027}{9} = -114\frac{1}{9} = -114.11111111111111$$