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\frac{1}{3}x+\frac{1}{3}\left(-2\right)=\frac{3}{4}x
Use the distributive property to multiply \frac{1}{3} by x-2.
\frac{1}{3}x+\frac{-2}{3}=\frac{3}{4}x
Multiply \frac{1}{3} and -2 to get \frac{-2}{3}.
\frac{1}{3}x-\frac{2}{3}=\frac{3}{4}x
Fraction \frac{-2}{3} can be rewritten as -\frac{2}{3} by extracting the negative sign.
\frac{1}{3}x-\frac{2}{3}-\frac{3}{4}x=0
Subtract \frac{3}{4}x from both sides.
-\frac{5}{12}x-\frac{2}{3}=0
Combine \frac{1}{3}x and -\frac{3}{4}x to get -\frac{5}{12}x.
-\frac{5}{12}x=\frac{2}{3}
Add \frac{2}{3} to both sides. Anything plus zero gives itself.
x=\frac{2}{3}\left(-\frac{12}{5}\right)
Multiply both sides by -\frac{12}{5}, the reciprocal of -\frac{5}{12}.
x=\frac{2\left(-12\right)}{3\times 5}
Multiply \frac{2}{3} times -\frac{12}{5} by multiplying numerator times numerator and denominator times denominator.
x=\frac{-24}{15}
Do the multiplications in the fraction \frac{2\left(-12\right)}{3\times 5}.
x=-\frac{8}{5}
Reduce the fraction \frac{-24}{15} to lowest terms by extracting and canceling out 3.