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\frac{1}{3}\times 5x+\frac{1}{3}\times 6-\frac{1}{2}\left(x+7\right)=2
Use the distributive property to multiply \frac{1}{3} by 5x+6.
\frac{5}{3}x+\frac{1}{3}\times 6-\frac{1}{2}\left(x+7\right)=2
Multiply \frac{1}{3} and 5 to get \frac{5}{3}.
\frac{5}{3}x+\frac{6}{3}-\frac{1}{2}\left(x+7\right)=2
Multiply \frac{1}{3} and 6 to get \frac{6}{3}.
\frac{5}{3}x+2-\frac{1}{2}\left(x+7\right)=2
Divide 6 by 3 to get 2.
\frac{5}{3}x+2-\frac{1}{2}x-\frac{1}{2}\times 7=2
Use the distributive property to multiply -\frac{1}{2} by x+7.
\frac{5}{3}x+2-\frac{1}{2}x+\frac{-7}{2}=2
Express -\frac{1}{2}\times 7 as a single fraction.
\frac{5}{3}x+2-\frac{1}{2}x-\frac{7}{2}=2
Fraction \frac{-7}{2} can be rewritten as -\frac{7}{2} by extracting the negative sign.
\frac{7}{6}x+2-\frac{7}{2}=2
Combine \frac{5}{3}x and -\frac{1}{2}x to get \frac{7}{6}x.
\frac{7}{6}x+\frac{4}{2}-\frac{7}{2}=2
Convert 2 to fraction \frac{4}{2}.
\frac{7}{6}x+\frac{4-7}{2}=2
Since \frac{4}{2} and \frac{7}{2} have the same denominator, subtract them by subtracting their numerators.
\frac{7}{6}x-\frac{3}{2}=2
Subtract 7 from 4 to get -3.
\frac{7}{6}x=2+\frac{3}{2}
Add \frac{3}{2} to both sides.
\frac{7}{6}x=\frac{4}{2}+\frac{3}{2}
Convert 2 to fraction \frac{4}{2}.
\frac{7}{6}x=\frac{4+3}{2}
Since \frac{4}{2} and \frac{3}{2} have the same denominator, add them by adding their numerators.
\frac{7}{6}x=\frac{7}{2}
Add 4 and 3 to get 7.
x=\frac{7}{2}\times \frac{6}{7}
Multiply both sides by \frac{6}{7}, the reciprocal of \frac{7}{6}.
x=\frac{7\times 6}{2\times 7}
Multiply \frac{7}{2} times \frac{6}{7} by multiplying numerator times numerator and denominator times denominator.
x=\frac{6}{2}
Cancel out 7 in both numerator and denominator.
x=3
Divide 6 by 2 to get 3.