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\frac{1}{3}\left(2-\sqrt{3}x\right)=1-2\sqrt{3}x
Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.
\frac{1}{3}\left(2-\sqrt{3}x\right)+2\sqrt{3}x=1
Add 2\sqrt{3}x to both sides.
\frac{1}{3}\times 2+\frac{1}{3}\left(-1\right)\sqrt{3}x+2\sqrt{3}x=1
Use the distributive property to multiply \frac{1}{3} by 2-\sqrt{3}x.
\frac{2}{3}+\frac{1}{3}\left(-1\right)\sqrt{3}x+2\sqrt{3}x=1
Multiply \frac{1}{3} and 2 to get \frac{2}{3}.
\frac{2}{3}-\frac{1}{3}\sqrt{3}x+2\sqrt{3}x=1
Multiply \frac{1}{3} and -1 to get -\frac{1}{3}.
\frac{2}{3}+\frac{5}{3}\sqrt{3}x=1
Combine -\frac{1}{3}\sqrt{3}x and 2\sqrt{3}x to get \frac{5}{3}\sqrt{3}x.
\frac{5}{3}\sqrt{3}x=1-\frac{2}{3}
Subtract \frac{2}{3} from both sides.
\frac{5}{3}\sqrt{3}x=\frac{3}{3}-\frac{2}{3}
Convert 1 to fraction \frac{3}{3}.
\frac{5}{3}\sqrt{3}x=\frac{3-2}{3}
Since \frac{3}{3} and \frac{2}{3} have the same denominator, subtract them by subtracting their numerators.
\frac{5}{3}\sqrt{3}x=\frac{1}{3}
Subtract 2 from 3 to get 1.
\frac{5\sqrt{3}}{3}x=\frac{1}{3}
The equation is in standard form.
\frac{3\times \frac{5\sqrt{3}}{3}x}{5\sqrt{3}}=\frac{\frac{1}{3}\times 3}{5\sqrt{3}}
Divide both sides by \frac{5}{3}\sqrt{3}.
x=\frac{\frac{1}{3}\times 3}{5\sqrt{3}}
Dividing by \frac{5}{3}\sqrt{3} undoes the multiplication by \frac{5}{3}\sqrt{3}.
x=\frac{\sqrt{3}}{15}
Divide \frac{1}{3} by \frac{5}{3}\sqrt{3}.