Solve for y
y=0
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2\left(\frac{1}{2}-2y\right)+3\left(1\times 2+1\right)y=1
Multiply both sides of the equation by 6, the least common multiple of 3,2,6.
2\times \frac{1}{2}-4y+3\left(1\times 2+1\right)y=1
Use the distributive property to multiply 2 by \frac{1}{2}-2y.
1-4y+3\left(1\times 2+1\right)y=1
Cancel out 2 and 2.
1-4y+3\left(2+1\right)y=1
Multiply 1 and 2 to get 2.
1-4y+3\times 3y=1
Add 2 and 1 to get 3.
1-4y+9y=1
Multiply 3 and 3 to get 9.
1+5y=1
Combine -4y and 9y to get 5y.
5y=1-1
Subtract 1 from both sides.
5y=0
Subtract 1 from 1 to get 0.
y=0
Product of two numbers is equal to 0 if at least one of them is 0. Since 5 is not equal to 0, y must be equal to 0.
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{ x } ^ { 2 } - 4 x - 5 = 0
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y = 3x + 4
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Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}