Solve 1/3*(14*14)*25-1/3(7*7)*y=81

$$\frac { 1 } { 3 } \times ( 14 \times 14 ) \times 25 - \frac { 1 } { 3 } ( 7 \times 7 ) \times y = 81$$

Solve for y

$$y = \frac{4657}{49} = 95\frac{2}{49} \approx 95.040816327$$

Steps for Solving Linear Equation

Multiply \frac{1}{3} and 14 to get \frac{14}{3}.

$$\frac{14}{3}\times 14\times 25-\frac{1}{3}\times 7\times 7y=81$$

Express \frac{14}{3}\times 14 as a single fraction.

$$\frac{14\times 14}{3}\times 25-\frac{1}{3}\times 7\times 7y=81$$

Multiply 14 and 14 to get 196.

$$\frac{196}{3}\times 25-\frac{1}{3}\times 7\times 7y=81$$

Express \frac{196}{3}\times 25 as a single fraction.

$$\frac{196\times 25}{3}-\frac{1}{3}\times 7\times 7y=81$$

Multiply 196 and 25 to get 4900.

$$\frac{4900}{3}-\frac{1}{3}\times 7\times 7y=81$$

Multiply \frac{1}{3} and 7 to get \frac{7}{3}.

$$\frac{4900}{3}-\frac{7}{3}\times 7y=81$$

Express \frac{7}{3}\times 7 as a single fraction.

$$\frac{4900}{3}-\frac{7\times 7}{3}y=81$$

Multiply 7 and 7 to get 49.

$$\frac{4900}{3}-\frac{49}{3}y=81$$

Subtract \frac{4900}{3} from both sides.

$$-\frac{49}{3}y=81-\frac{4900}{3}$$

Convert 81 to fraction \frac{243}{3}.

$$-\frac{49}{3}y=\frac{243}{3}-\frac{4900}{3}$$

Since \frac{243}{3} and \frac{4900}{3} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{49}{3}y=\frac{243-4900}{3}$$

Subtract 4900 from 243 to get -4657.

$$-\frac{49}{3}y=-\frac{4657}{3}$$

Multiply both sides by -\frac{3}{49}, the reciprocal of -\frac{49}{3}.

$$y=-\frac{4657}{3}\left(-\frac{3}{49}\right)$$

Multiply -\frac{4657}{3} times -\frac{3}{49} by multiplying numerator times numerator and denominator times denominator.

$$y=\frac{-4657\left(-3\right)}{3\times 49}$$

Do the multiplications in the fraction \frac{-4657\left(-3\right)}{3\times 49}.

$$y=\frac{13971}{147}$$

Reduce the fraction \frac{13971}{147} to lowest terms by extracting and canceling out 3.

$$y=\frac{4657}{49}$$