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\frac{4}{3}\sqrt[3]{9}+\frac{1}{2}+\frac{1}{6}\sqrt[3]{9}
Combine \frac{1}{3}\sqrt[3]{9} and \sqrt[3]{9} to get \frac{4}{3}\sqrt[3]{9}.
\frac{3}{2}\sqrt[3]{9}+\frac{1}{2}
Combine \frac{4}{3}\sqrt[3]{9} and \frac{1}{6}\sqrt[3]{9} to get \frac{3}{2}\sqrt[3]{9}.