Solve 1/3div6/7+2/3div6/7

$$\frac { 1 } { 3 } \div \frac { 6 } { 7 } + \frac { 2 } { 3 } \div \frac { 6 } { 7 }$$

Evaluate

$$\frac{7}{6}\approx 1.166666667$$

Solution Steps

Divide \frac{1}{3} by \frac{6}{7} by multiplying \frac{1}{3} by the reciprocal of \frac{6}{7}.

$$\frac{1}{3}\times \frac{7}{6}+\frac{\frac{2}{3}}{\frac{6}{7}}$$

Multiply \frac{1}{3} times \frac{7}{6} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 7}{3\times 6}+\frac{\frac{2}{3}}{\frac{6}{7}}$$

Do the multiplications in the fraction \frac{1\times 7}{3\times 6}.

$$\frac{7}{18}+\frac{\frac{2}{3}}{\frac{6}{7}}$$

Divide \frac{2}{3} by \frac{6}{7} by multiplying \frac{2}{3} by the reciprocal of \frac{6}{7}.

$$\frac{7}{18}+\frac{2}{3}\times \frac{7}{6}$$

Multiply \frac{2}{3} times \frac{7}{6} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7}{18}+\frac{2\times 7}{3\times 6}$$

Do the multiplications in the fraction \frac{2\times 7}{3\times 6}.

$$\frac{7}{18}+\frac{14}{18}$$

Since \frac{7}{18} and \frac{14}{18} have the same denominator, add them by adding their numerators.

$$\frac{7+14}{18}$$

Add 7 and 14 to get 21.

$$\frac{21}{18}$$

Reduce the fraction \frac{21}{18} to lowest terms by extracting and canceling out 3.

$$\frac{7}{6}$$

Factor

$$\frac{7}{2 \cdot 3} = 1\frac{1}{6} = 1.1666666666666667$$