Solve 1/3*(-9/4)+13*10

$$\frac { 1 } { 3 } \cdot ( - \frac { 9 } { 4 } ) + 13 \cdot 10$$

Evaluate

$$\frac{517}{4}=129.25$$

Solution Steps

Multiply \frac{1}{3} times -\frac{9}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\left(-9\right)}{3\times 4}+13\times 10$$

Do the multiplications in the fraction \frac{1\left(-9\right)}{3\times 4}.

$$\frac{-9}{12}+13\times 10$$

Reduce the fraction \frac{-9}{12} to lowest terms by extracting and canceling out 3.

$$-\frac{3}{4}+13\times 10$$

Multiply 13 and 10 to get 130.

$$-\frac{3}{4}+130$$

Convert 130 to fraction \frac{520}{4}.

$$-\frac{3}{4}+\frac{520}{4}$$

Since -\frac{3}{4} and \frac{520}{4} have the same denominator, add them by adding their numerators.

$$\frac{-3+520}{4}$$

Add -3 and 520 to get 517.

$$\frac{517}{4}$$

Factor

$$\frac{11 \cdot 47}{2 ^ {2}} = 129\frac{1}{4} = 129.25$$