Solve 1/3*3/3*1/3*4-2=

$$\frac { 1 } { 3 } \cdot \frac { 3 } { 3 } \cdot \frac { 1 } { 3 } \cdot 4 - 2 =$$

Evaluate

$$-\frac{14}{9}\approx -1.555555556$$

Solution Steps

Divide 3 by 3 to get 1.

$$\frac{1}{3}\times 1\times \frac{1}{3}\times 4-2$$

Multiply \frac{1}{3} and 1 to get \frac{1}{3}.

$$\frac{1}{3}\times \frac{1}{3}\times 4-2$$

Multiply \frac{1}{3} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 1}{3\times 3}\times 4-2$$

Do the multiplications in the fraction \frac{1\times 1}{3\times 3}.

$$\frac{1}{9}\times 4-2$$

Multiply \frac{1}{9} and 4 to get \frac{4}{9}.

$$\frac{4}{9}-2$$

Convert 2 to fraction \frac{18}{9}.

$$\frac{4}{9}-\frac{18}{9}$$

Since \frac{4}{9} and \frac{18}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4-18}{9}$$

Subtract 18 from 4 to get -14.

$$-\frac{14}{9}$$

Factor

$$-\frac{14}{9} = -1\frac{5}{9} = -1.5555555555555556$$